You are standing 2.5m directly in front of one of two loudspeakers. they are 3m apart and both are playing a 686hz tone in phase. As you begin to walk directly away from the speaker, at what distances from the speaker do you hear a minimum sound intensity? Assume speed of sound of 343m/s
The Attempt at a Solution
I've been trying to approach the problem using the idea that the minimum sound intensity will occur where the waves experience destructive interference, which will happen when they are a half-wavelength apart in phase.
so the wavelength can be calculated at .5m,
So r = phase difference.
r = wavelength*.5
then, by the Pythagorean Theorem. r = (15.25 + 5x + 5x^2)^.5 -(2.5 + x)
where x is the distance from the starting point.
Is this the correct approach to take?