Two loudspeakers emit sound waves of the same frequency along the x-axis. The amplitude of each wave is a. The sound intensity is minimum when speaker 2 is 10 cm behind speaker 1. The intensity increases as speaker 2a is moved forward and first reaches maximum, with amplitude 2 a, when it is 30 cm in front of speaker 1.
What is the amplitude of the sound if the speakers are placed side by side?
ΔΦ = 2π[(Δx)/λ] = 2mπ , m = 0,1,2,3...
The Attempt at a Solution
I found the following:
λ = 80cm
Phase difference = ¾π (0.75π) =~ 2.36radians
I tried drawing it but I am not getting the correct answer, and I don't know what to do...