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Wave interference question
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[QUOTE="TSny, post: 5676542, member: 229090"] If the screen is "far" from the slits (L >> d) then there is a formula for the angle θ representing the direction to the first minimum (destructive interference). This formula is based on the "path difference" from the two slits being approximated as d⋅sin θ. Using the condition on the path difference for a minimum, you can calculate θ. Then, using geometry, you can find the distance from the perpendicular bisector to the location of the minimum at the end of the tank. This is how I got my result of 1.29 m. However, I now realize that the assumption L >> d does not hold in your problem. So, d⋅sin θ is not accurate for the path difference. Using geometry you can find an accurate expression for the path difference, but it is more complicated. If I redo the calculation without any approximations, I get 1.31 m for the data given in the solution. Since the solution uses the approximate formula, I would guess that you are OK with working the problem as you did. But, keep in mind that your answer is only an approximation. Without approximation, I get 1.21 m instead of 0.90 m. So, you can see that your approximated answer is not very accurate. [/QUOTE]
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Wave interference question
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