I Wave packet integral question

upload_2016-11-7_15-20-40.png


Hi,

what kind if integration used on equation 1 so it turned into equation 2? this does not look like integration by parts. and where (x-x0) appeared from instead of (k-k0) ?

thanks for your help.
 

DrClaude

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No integration was done. For instance, for the imaginary term, you multiply by the right-hand side by ##\exp[i k_0(x-x_0)] \exp[-i k_0(x-x_0)]##, and move the second exponential inside the integral sign.
 

andrewkirk

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No integration has been done yet. It's the old mathematical trick of multiplying and dividing by the same thing.
Outside the integral is a factor of
$$\exp\left[-\frac{(x-x_0)^2}2(\Delta k)^2\right]$$
and inside the integral is a factor of the reciprocal
$$\exp\left[\frac{(x-x_0)^2}2(\Delta k)^2\right]$$
These cancel each other out.

They can be freely moved through the integral sign because they do not involve the integration variable ##k##.

EDIT: Darn, Dr Claude jinxed me. Now I'm not allowed to talk for the rest of the day.
 

dextercioby

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I bet you are reading from a Russian book translated into English decades ago.
 
I bet you are reading from a Russian book translated into English decades ago.
:D I have many of those books too.
But this image is from David Bohm's Quantum Theory.
 

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