Wave paddle application Integration problem

  • Thread starter gl0ck
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  • #1
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Homework Statement



This is an engineering design application, but It contains integration. Sorry if I didnt post it in the right folder.


I think a)'s answer should be (pgw)^2*h^2
h=r
To be honest no Idea what is going on..

Thanks
 

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Answers and Replies

  • #2
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Homework Statement



This is an engineering design application, but It contains integration. Sorry if I didnt post it in the right folder.


I think a)'s answer should be (pgw)^2*h^2
h=r
To be honest no Idea what is going on..

Thanks

What do the values 'p', 'g' and 'w' represent?

If they are just constants, then remove them from the integrand.
Eg.
gif.gif
 
  • #3
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So, I think I've figured out 1a) ,b) ,c)
1a)
(pgwH^2)/2
1b)
Fo=-(pgwH^3)/3
1c)
θ=βsin(ωt)
dθ/dt=ωβcos(ωt)
d^2θ/dt=ω^2βsin(ωt)

Q2 gets something like:
T=-(pgwH^3)/3+Bωβcos(-tan^(-1)(Aω/B))-Aω^2βsin(tan^(-1)(Aω/B)
which seems a bit complicated to be integrated, because we have to find first its derivetive..
Thanks
 
  • #4
haruspex
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1b)
Fo=-(pgwH^3)/3
I don't think the coefficient is 1/3. Please post your working.
1c)
θ=βsin(ωt)
dθ/dt=ωβcos(ωt)
d^2θ/dt=ω^2βsin(ωt)
Check your signs.
T=-(pgwH^3)/3+Bωβcos(-tan^(-1)(Aω/B))-Aω^2βsin(tan^(-1)(Aω/B)
which seems a bit complicated to be integrated, because we have to find first its derivetive..
You can simplify cos(arctan(x)) so as not to involve any trig. I think you have a sign wrong, propagated through from 1c. What makes you think you need to integrate this?
 

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