Do Muons and Electrons with the Same Kinetic Energy Share Identical Wavelengths?

In summary, the discussion is about a statement made by a student regarding the relationship between the energy and wavelength of muons and electrons. The statement is deemed incorrect by one of the participants, who explains the reasoning behind it. The equation E=hc/\lambda is mentioned, but it is clarified that it is only valid for massless particles traveling at the speed of light. The question is then clarified to assume that both muons and electrons have the same kinetic energy.
  • #1
JaWiB
285
0

Homework Statement



Consider the statement below made by a student: "Muons have a higher mass than electrons, but because the energy, E, is related to the wavelength by E=hc/[tex]\lambda[/tex], muons that have the same kinetic energy as electrons will also have the same wavelength."

Do you agree or disagree with this statement? Explain your reasoning.

Homework Equations



[tex]\lambda=h/p[/tex] (de Broglie wavelength)

The Attempt at a Solution



The statement seems wrong to me. If you substitute in for [tex]\lambda[/tex] in the first equation, you get cp, but kinetic energy is p^2/(2m) and those two can't be the same (solving for c gives c=v/2).

I'd never seen the first equation before, but looking in my textbook it looks like E is the change in energy of an atom when a photon is absorbed or emitted and I don't know how you could apply it to an electron/muon (can you?)
 
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  • #2
[itex]\lambda[/itex] is different for different objects, so why should E be the same?

E is the total relativistic energy, not p^2/2m. Also, E = hf, where f is the frequency associated with the de Broglie wave.

Just do the simple math. Also, reading up on de Broglie wavelength would be a good idea.

EDIT:
-----

Are you talking about the muons and the electrons having the same energy, by any chance? This is not mentioned in the problem, so I assumed not.

Also, [itex]E=hc/\lambda[/itex] is valid only for massless particles which travel at speed c.
 
Last edited:
  • #3
>[itex]\lambda[/itex] is different for different objects, so why should E be the same?
The question is assuming you have two particles with the same kinetic energy.

>For high speed particles, E is the total relativistic energy, not p^2/2m.
Ok, but I still doubt that cp=Ek for an electron. Is that wrong?

>Also, E = hf, where f is the frequency associated with the de Broglie wave.
And if f=v/[tex]\lambda[/tex], then E = vp. But v can't be c for an electron, so the equation can't work here (?)
 
  • #4
Sorry, you posted while I was replying. Yes, that's the problem:
"muons that have the same kinetic energy as electrons..."

>Also, is valid only for massless particles which travel at speed c.

I'm guessing this is essentially the answer to the question
 

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