- #1

timtng

- 25

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v=fλ, f=v/λ =(600m/s)/3m = 200Hz

T=1/f=1/200=.005s

t=T/2 = .0025s Is this answer correct?

Thanks

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- Thread starter timtng
- Start date

- #1

timtng

- 25

- 0

v=fλ, f=v/λ =(600m/s)/3m = 200Hz

T=1/f=1/200=.005s

t=T/2 = .0025s Is this answer correct?

Thanks

- #2

Ambitwistor

- 841

- 1

Yes.

- #3

timtng

- 25

- 0

Standing waves are produced on a string for which the velocity of transverse waves is 200 m/s. The frequency of vibration is 500 Hz. How far apart are the nodes?

I can only find λ, λ=v/f=200/500=.4m

I don't know how to finish the rest of the problem

- #4

Ambitwistor

- 841

- 1

- #5

timtng

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So the answer should be λ/2?

- #6

Ambitwistor

- 841

- 1

Originally posted by timtng

So the answer should be λ/2?

Yes, that's what "half-wavelength" means.

- #7

timtng

- 25

- 0

shouldn't the answer be: L-λ/2

- #8

Ambitwistor

- 841

- 1

Originally posted by timtng

shouldn't the answer be: L-λ/2

No, why?

- #9

timtng

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I figured since they ask how far apart are the nodes, L has to be a contributing factor.

- #10

Ambitwistor

- 841

- 1

Originally posted by timtng

I figured since they ask how far apart are the nodes, L has to be a contributing factor.

L will be some integer multiple of λ/2, but if you already know λ, it doesn't matter what L is. L just dictates how many nodes there are.

- #11

HallsofIvy

Science Advisor

Homework Helper

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I figured since they ask how far apart are the nodes, L has to be a contributing factor.

Did you notice that there was no "L" given in the problem?

We were given, instead, the frequency.

If you were given the wavespeed (determined by the mass and tension of the string) and length, then you could find the frequency. Here, that's not necessary.

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