A wire with an alternating current flowing through it is placed in a magnetic field. This causes the wire to oscillate with a frequency equal to the frequency of the current (you will learn about this when we study electromagnetism). The wire has a length (length is measured from the node at which the wire is tied to the pulley) L = 2.46 m. A mass of 244.0 g is hung on the end of the wire. The frequency of the current is initially set to f = 59.8 Hz. Three loops are observed in the wire at this frequency as shown in the diagram.
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The Attempt at a Solution
µ = T/(2Lf)2 =(0.244*9.8)/(2* 2.46m*59.8 Hz)^2
This answer was wrong according when inserted!
Any help finding the velocity or the mass per unit length is kindly appreciated!