- #1

davieddy

- 181

- 0

fixed wiggly tube at speed v.

At any point, the tube's wiggly curve has a well-defined centre of curvature,

and associated radius r.

The acceleration of the string is v^2/r, and the force due to tension T is

T*dl/r where dl is the length of an element of string. Both directed towards the

centre of curvature.

If T*dl/r = m*dl*v^2/r (m being mass/unit length) then there is no need for

the tube!

v^2 = T/m and there is no restriction on the waveform.

Comments?

David