Calculating Wavelength of Electron Emission

[Air]

I need to make sure my method and the formula I have used is correct. Also, my answer for the wavelength seems slightly dodgy. :uhh:

Homework Statement

An electron recombines with a hole losing 2.6eV of electrical potential energy. Calculate the wavelength of the light emitted.

Homework Equations

Not given. Equations have to be used ourself.

The Attempt at a Solution

$E = \frac{hc}{\lambda}$

$\lambda = \frac{hc}{E}$

$\lambda = \frac{(6.63 \times 10^{-34})(3.00 \times 10^8)}{2.6}$

$\lambda = 7.65 \times 10^{-26}m$

 

[Dick]

Put units on things and make sure they match up. You'll want to convert 2.6eV to joules.

 

[AstroRoyale]

You've found the most high energy photon I've ever heard of! ! ! ! Always check the units, you forgot to convert the energy from eV's to Joules.

and I see now that dick just recommended the same thing. . .

 

[Air]

How would I change eV's to Joules?

 

[Dick]

1eV=1.60217646*10^(-19) joules. That's what google says when I type in 'electron volt', anyway.