Wavelength, Electron

  • Thread starter Air
  • Start date
  • #1
Air
203
0
I need to make sure my method and the formula I have used is correct. Also, my answer for the wavelength seems slightly dodgy. :uhh:

Homework Statement


An electron recombines with a hole losing 2.6eV of electrical potential energy. Calculate the wavelength of the light emitted.


Homework Equations


Not given. Equations have to be used ourself.


The Attempt at a Solution


[itex]E = \frac{hc}{\lambda}[/itex]

[itex]\lambda = \frac{hc}{E}[/itex]

[itex]\lambda = \frac{(6.63 \times 10^{-34})(3.00 \times 10^8)}{2.6}[/itex]

[itex]\lambda = 7.65 \times 10^{-26}m[/itex]
 

Answers and Replies

  • #2
Dick
Science Advisor
Homework Helper
26,259
621
Put units on things and make sure they match up. You'll want to convert 2.6eV to joules.
 
  • #3
AstroRoyale
110
0
You've found the most high energy photon I've ever heard of! ! ! ! Always check the units, you forgot to convert the energy from eV's to Joules.

and I see now that dick just recommended the same thing. . .
 
Last edited:
  • #4
Air
203
0
How would I change eV's to Joules?
 
  • #5
Dick
Science Advisor
Homework Helper
26,259
621
1eV=1.60217646*10^(-19) joules. That's what google says when I type in 'electron volt', anyway.
 

Suggested for: Wavelength, Electron

Replies
8
Views
252
  • Last Post
Replies
6
Views
274
Replies
4
Views
613
  • Last Post
Replies
1
Views
469
  • Last Post
Replies
3
Views
329
Replies
5
Views
554
  • Last Post
Replies
14
Views
642
Replies
2
Views
621
  • Last Post
Replies
3
Views
333
Replies
14
Views
2K
Top