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## Homework Statement

Calculate the shortest wavelength photon that is emitted in the hydrogen atom.

Energy when n = 1 = -13.6 eV

## Homework Equations

E = hc/λ

λ = hc/E

## The Attempt at a Solution

Well as far as I understand, when the electron is in the n = 1 energy level it has it's lowest energy, which is -13.6 eV. I believe this is where the shortest wavelength will be...

λ = hc/E

= (4.14 x 10^-15 eV*s)(3.00 x 10^8 m/s) / -13.6 eV

= approx 9.13 x 10^-8 m

Was my method correct? I would really just like a second opinion. Thank you!