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Hello there,

For the following problem, I am arriving at an answer different from the given one so I would appreciate any help or hints.

Thank you. My work is shown below.

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1. A slightly smaller plastic pipe is inserted inside a second plastic pipe to produce an air column, open at both ends, whose lengths can be varied from 35 cm to 65 cm. A loud speaker, connected to an audio frequency generator, is held over one of the open ends. As the length of the air column is increased, resonance is heard first when the air column is 38 cm long and again when it is 57 cm long.

a) Calculate the wavelength of the sound produced by the audio frequency generator.

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Since the first resonant length is 38 cm long:

[itex] L = \frac {\lambda}{2} [/itex]

[itex] 0.38 m = \frac {\lambda}{2} [/itex]

[itex] \lambda = 0.76 m [/itex]

However, my textbook says that it is 0.38 m.

For the following problem, I am arriving at an answer different from the given one so I would appreciate any help or hints.

Thank you. My work is shown below.

---

1. A slightly smaller plastic pipe is inserted inside a second plastic pipe to produce an air column, open at both ends, whose lengths can be varied from 35 cm to 65 cm. A loud speaker, connected to an audio frequency generator, is held over one of the open ends. As the length of the air column is increased, resonance is heard first when the air column is 38 cm long and again when it is 57 cm long.

a) Calculate the wavelength of the sound produced by the audio frequency generator.

---

Since the first resonant length is 38 cm long:

[itex] L = \frac {\lambda}{2} [/itex]

[itex] 0.38 m = \frac {\lambda}{2} [/itex]

[itex] \lambda = 0.76 m [/itex]

However, my textbook says that it is 0.38 m.

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