# Wavelengths and Frequency

## Homework Statement

Particles approximately 3.0 x 10^-2 cm in diameter are to be scrubbed loose from machine parts in an aqueous ultrasonic cleaning bath. Above what frequency should the bath be operated to produce wavelengths of this size and smaller?

Fn = nv/(2L)
v= SQRT(F/Mew)
Mew=m/L
L=(n/2)Lambada
f=v/(lambada)

## The Attempt at a Solution

So far I cannot come up with a beginning place on this one... I am thinking about using f=v/(lambada) but how would i come up with the velocity (v) without mew or F?

## Answers and Replies

Related Introductory Physics Homework Help News on Phys.org
learningphysics
Homework Helper
I think you just need to use: frequency = (speed of light)/wavelength

Use wavelength = 3.0*10^-2cm = 3.0*10^-4m

mgb_phys
Science Advisor
Homework Helper
It's an ultrasound cleaner so it's not the speed of light - it would be the speed of sound in the liquid.
You could just quote the frequency in terms of sound speed if you don't have a value.

learningphysics
Homework Helper
It's an ultrasound cleaner so it's not the speed of light - it would be the speed of sound in the liquid.
You could just quote the frequency in terms of sound speed if you don't have a value.
Oops. Sorry about that. 