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Wavenumber, transitions

  • Thread starter rayman123
  • Start date
152
0
1. Homework Statement
Calculate a diameter of an H-atom with n=732. Calculate also the value of the wavenumber corresponding to the transition from n=732 to n=731




2. Homework Equations

[tex] E_{trans}= \frac{-E_{h}}{(732)^2}-\frac{-E_{h}}{(731)^2}}[/tex]



3. The Attempt at a Solution

[tex] E_{trans}= \frac{-13.6}{(732)^2}-\frac{-13.6}{(731)^2}}=6.95\cdot10^{-5} eV[/tex]

[tex] E=\frac{hc}{\lambda}\Rightarrow \lambda=\frac{hc}{E}=\frac{4.135\cdot10^{-15}\cdot 3\cdot10^8}{6.95\cdot10^{-5}}=0.0178 m[/tex]
1. Homework Statement

now going back to the wavenumber, i was not sure which formula i should use....
[tex] k=\frac{2\pi}{\lambda} or \nu=\frac{1}{\lambda}[/tex]
I have chosen the second one and i got
[tex] \nu=\frac{1}{0.0178}=56.18 m^{-1}[/tex]
1. Homework Statement

Is that a relevant result?







3. The Attempt at a Solution

the diameter will be=
[tex] d_{n}=2\cdot r_{0}\cdot n^2= 2\cdot (732)^2\cdot 5.291\cdot10^{-5} = 5.67\cdot10^{-5} m[/tex]
 
Last edited:
93
0
Seems OK :)
 

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