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**1. Homework Statement**

Calculate a diameter of an H-atom with n=732. Calculate also the value of the wavenumber corresponding to the transition from n=732 to n=731

**2. Homework Equations**

[tex] E_{trans}= \frac{-E_{h}}{(732)^2}-\frac{-E_{h}}{(731)^2}}[/tex]

**3. The Attempt at a Solution**

[tex] E_{trans}= \frac{-13.6}{(732)^2}-\frac{-13.6}{(731)^2}}=6.95\cdot10^{-5} eV[/tex]

[tex] E=\frac{hc}{\lambda}\Rightarrow \lambda=\frac{hc}{E}=\frac{4.135\cdot10^{-15}\cdot 3\cdot10^8}{6.95\cdot10^{-5}}=0.0178 m[/tex]

**1. Homework Statement**

now going back to the wavenumber, i was not sure which formula i should use....

[tex] k=\frac{2\pi}{\lambda} or \nu=\frac{1}{\lambda}[/tex]

I have chosen the second one and i got

[tex] \nu=\frac{1}{0.0178}=56.18 m^{-1}[/tex]

**1. Homework Statement**

Is that a relevant result?

**3. The Attempt at a Solution**

the diameter will be=

[tex] d_{n}=2\cdot r_{0}\cdot n^2= 2\cdot (732)^2\cdot 5.291\cdot10^{-5} = 5.67\cdot10^{-5} m[/tex]

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