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Waves in a Tube

  1. Apr 25, 2009 #1
    1. The problem statement, all variables and given/known data

    A tube closed at one end and open at the other has a fundamental frequency of 242 Hz. What is the fundamental whenboth are open?

    2. Relevant equations

    f (open and closed) = v/4L
    f (open) = v/2L
    v sound = 343 m/s

    3. The attempt at a solution

    f1 (open and closed) = v/4L = 242Hz = 343/4L

    L = .354 m

    f (open) = v /2L = 343/ 2(.354m) = 484 Hz

    Does this look OK?
     
  2. jcsd
  3. Apr 26, 2009 #2

    Doc Al

    User Avatar

    Staff: Mentor

    Looks good.
     
  4. Apr 26, 2009 #3
    Great. Thanks for looking!
     
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