1. Apr 25, 2009 #1

   veronicak5678

   

   1. The problem statement, all variables and given/known data
   
   A tube closed at one end and open at the other has a fundamental frequency of 242 Hz. What is the fundamental whenboth are open?
   
   2. Relevant equations
   
   f (open and closed) = v/4L
   f (open) = v/2L
   v sound = 343 m/s
   
   3. The attempt at a solution
   
   f1 (open and closed) = v/4L = 242Hz = 343/4L
   
   L = .354 m
   
   f (open) = v /2L = 343/ 2(.354m) = 484 Hz
   
   Does this look OK?

    

   veronicak5678, Apr 25, 2009
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3. Apr 26, 2009 #2

   Doc Al

   

   Staff: Mentor

   Looks good.

    

   Doc Al, Apr 26, 2009
4. Apr 26, 2009 #3

   veronicak5678

   

   Great. Thanks for looking!

    

   veronicak5678, Apr 26, 2009

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