Waves: Standing Waves, Superposition, etc.

  • Thread starter dekoi
  • Start date
  • #1
dekoi
1.) S and P waves, simultaneously radiated from the hypocenter of an earthquake, are received at a seismographic station 17.3 s apart. Assume the waves have traveled over the same path at speeds of 4.50 km/s and 7.80 km/s. Find the distance from the seismograph to the hypocenter of the quake.

The text doesn't thoroughly explain how to do these types of questions. So, I can't even explain what I did, since i have no beginning point.

2.) Two waves in one string are described by

y1 = 3cos(4x - 1.6t)
y2 = 4sin(5x - 2t)

Find superposition.

The formula I have for the addition of two wave functions requires both functions to be sin and also for the amplitudes to be equal. So, I made y1 = 3sin(4x - 1.6 - pi/2). However, how do i deal with the uncommon bases?

3.) Two pulses travel on string are described as functions:

y1 = 5 / ( (3x - 4t)^2 + 2)

y2 = -5 / ( (3x + 4t - 6t^2) + 2)

When will the two waves cancel everywhere? At what point to the two pulses always cancel?

I noticed that that y2 is reflected on the x-axis, and has a phase constant. Also, it is moving to the left, while y1 moves to the right.

Firstly, what are the conditions under which the waves will cancel everywhere? For two waves to cancel everywhere, would they not have to have equal phase constants (which these do not?

Also, what are the conditions for the waves to cancel? I propose that the functions be added, and the values be found which would cause y to equal = 0. However, there is both x and t variables!

Thank you for any help you can provide on this urgen issue.
 

Answers and Replies

  • #2
mezarashi
Homework Helper
650
0
dekoi said:
1.) S and P waves, simultaneously radiated from the hypocenter of an earthquake, are received at a seismographic station 17.3 s apart. Assume the waves have traveled over the same path at speeds of 4.50 km/s and 7.80 km/s. Find the distance from the seismograph to the hypocenter of the quake.
Not much of a physics question, but rather a math teaser. You know that distance = velocity x time. Now you don't know distance, but you know they are equal:

d1 = v1 x t1, v1 = 4.5km/s (1)
d1 = v2 x t2, v2 = 7.8km/s (2)

You also know that (t2-t1) = 17.3 (3)
Three unknown variables (d1, t1, t2), three equations as listed. Solved.

dekoi said:
2.) Two waves in one string are described by

y1 = 3cos(4x - 1.6t)
y2 = 4sin(5x - 2t)

Find superposition.
By definition, I believe the superposition is simply the addition of the two functions y1 + y2. They are of different frequency and will not interfere with each others signal. Or better stated, the field caused by a number of sources is determined by adding the individual fields together.

dekoi said:
3.) Two pulses travel on string are described as functions:

y1 = 5 / ( (3x - 4t)^2 + 2)
y2 = -5 / ( (3x + 4t - 6t^2) + 2)

When will the two waves cancel everywhere? At what point to the two pulses always cancel?
For the pulses to cancel everywhere, then you must equate
y1 + y2 = 0, for all x. Solve for t. I can see the math getting pretty ugly however.

The second part is the opposite of the first. At what point/points do the two pulses always cancel. The condition here is then.
y1 + y2 = 0, for all t. Solve for x. Again, may get ugly mathematically ^^;;
 
  • #3
dekoi said:
1.) S and P waves, simultaneously radiated from the hypocenter of an earthquake, are received at a seismographic station 17.3 s apart. Assume the waves have traveled over the same path at speeds of 4.50 km/s and 7.80 km/s. Find the distance from the seismograph to the hypocenter of the quake.

The text doesn't thoroughly explain how to do these types of questions. So, I can't even explain what I did, since i have no beginning point.


Thank you for any help you can provide on this urgent issue.
I think this is #5 is my homework, but you're from somewhere else. Interesting. Anyways, it took me a while to figure it out, here's the hints my teacher gave me.
x=vt. the two waves have the same distance, but different times and velocities. set the equation to solve for the known difference in time and you should get it from there.

I hope that wasn't too much info.
 
  • #4
dekoi
to: mezarashi

The second part is the opposite of the first. At what point/points do the two pulses always cancel. The condition here is then.
y1 + y2 = 0, for all t. Solve for x. Again, may get ugly mathematically
I tried this, and when I solved for x I ended up with x = 1.

I ended up with

x = 48t - 36 / 48t - 36 = 1

However, how do I solve for t?
 
Last edited by a moderator:
  • #5
well that means for any value of t other than t=36/48 sec the above equation will be satisfied
 

Related Threads on Waves: Standing Waves, Superposition, etc.

Replies
2
Views
958
Replies
0
Views
1K
Replies
11
Views
2K
Replies
2
Views
5K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
1
Views
488
  • Last Post
Replies
1
Views
4K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
5
Views
741
Top