Calculating Force P to Lift 200kg Crate: A Challenge!

In summary, the problem is to determine the force P required to lift a 200kg crate, with a coefficient of static friction of 0.3 on all contact surfaces. The equation μS x Fn = Fk can be used to find the friction force, and the normal force can be found by considering the weight of the crate and the P force.
  • #1
mike41
19
0

Homework Statement



Determine the force P required to like the 200kg crate. Coeff. Static friciton is 0.3 on ALL contact of surfaces. Neglect Wedge Mass

Prob.8-66.jpg


Homework Equations



μS x Fn = Fk
Summation of forces eqns

The Attempt at a Solution



im getting more unknowns than equations
see attachment.
 

Attachments

  • wedges.jpg
    wedges.jpg
    13.5 KB · Views: 386
Physics news on Phys.org
  • #2
You should be able to get the friction force due to the B wedge moving on the crate surface quite easily. Do that first!
For the next surface down, can you find the normal force? Both the weight of the crate and the P force contribute to it.
 
  • #3
haha ofund it actually. muFN = Fk so uu only have 2 variables. gah well thanks anyways
 

1. How do you calculate the force necessary to lift a 200kg crate?

The force required to lift a 200kg crate can be calculated using the formula F=ma, where F is the force, m is the mass of the crate (200kg), and a is the acceleration due to gravity (9.8 m/s^2). Therefore, the force required to lift a 200kg crate would be 1960 Newtons (N).

2. What other factors should be considered when calculating the force to lift a crate?

In addition to the mass of the crate, other factors that should be considered when calculating the force to lift a crate include the weight distribution of the load, the distance the crate needs to be lifted, and any external forces acting on the crate (such as friction or air resistance).

3. Is it possible to calculate the exact force needed to lift a crate?

While it is possible to calculate the theoretical force required to lift a crate, in reality there may be slight variations due to factors such as the strength and technique of the person lifting, and the conditions of the environment. Therefore, the calculated force should be used as an estimate rather than an exact measurement.

4. Can the force needed to lift a crate be reduced?

Yes, the force needed to lift a crate can be reduced by using a lever or pulley system, which can increase the mechanical advantage and require less force to lift the same load. Additionally, using proper lifting techniques and distributing the weight evenly can also reduce the force needed.

5. How can the force needed to lift a crate be increased?

The force needed to lift a crate can be increased by adding additional weight to the crate, increasing the distance the crate needs to be lifted, or increasing the acceleration due to gravity (by lifting the crate on a planet with a stronger gravitational pull, for example). However, it is important to note that increasing the force beyond what is necessary can be dangerous and should be done with caution.

Similar threads

  • Introductory Physics Homework Help
Replies
1
Views
963
  • Introductory Physics Homework Help
Replies
7
Views
1K
  • Introductory Physics Homework Help
Replies
10
Views
2K
  • Introductory Physics Homework Help
Replies
9
Views
3K
  • Introductory Physics Homework Help
Replies
3
Views
2K
  • Introductory Physics Homework Help
Replies
6
Views
5K
  • Introductory Physics Homework Help
Replies
4
Views
14K
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
2K
Back
Top