- #1

- 624

- 11

- I
- Thread starter Silviu
- Start date

- #1

- 624

- 11

- #2

- 16,829

- 6,650

Now, since the wedge product basis is anti-symmetric, adding something symmetric to the components will actually not matter at all (its contribution to the sum would be zero), but seen as just a type (0,r) tensor, its component would be anti-symmetric.

Note that ##\omega = \omega_{\mu\nu} dx^\mu \otimes dx^\nu## is

- #3

martinbn

Science Advisor

- 1,961

- 631

It would be ##\omega=\omega_{\mu\nu}dx^\mu \wedge dx^\nu##...If I have a 2-form, that would be ##\omega=\omega_{\mu\nu}dx^\mu dx^\nu##...

- Last Post

- Replies
- 4

- Views
- 6K

- Last Post

- Replies
- 8

- Views
- 3K

- Replies
- 3

- Views
- 4K

- Last Post

- Replies
- 32

- Views
- 9K

- Replies
- 6

- Views
- 7K

- Last Post

- Replies
- 11

- Views
- 5K

- Last Post

- Replies
- 4

- Views
- 835

- Last Post

- Replies
- 11

- Views
- 4K

- Replies
- 4

- Views
- 1K

- Last Post

- Replies
- 5

- Views
- 4K