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Weight + motion = torque

  1. Dec 28, 2007 #1
    The question is how to continue to elevate weight to produce motion that will give the end result torque? Motion will take place if wt is on one side, but lifting the wt on the same wheel balances and no rotation will occur. I believe if you have continued rotated wt on one side of a wheel it will continue to rotate and produce torque for work. I think if the wt is removed from the wheel at the bottom and rolled onto a balance scale and lifted by (stationary wt)at the other end of the scale this will elevate weight back to the top and released with multiple weights already in rotation on the wheel. To bring the balance scale down, leverage is needed. The leverage bar must rotate with the multiple weight wheel and bring the balance scale back down to catch the next weight in rotation. The leverage bar will release the balance scale once the weight is in place by way of a henge and a pin. The one wt will henge and cause the pin to be pulled and the leverage bar will rotate back to the top, the stationary wt elevates the rotation wt and the leverage bar will bring the balance scale down after the scale has released the wt on the wheel. I know this is very simple but is possible. Do the math. Work can be produced with continued rotation of wt. Thank you gravity. My name is Newton and I hope when you look at this you say, damn that is stupid. p.s It is possible, do the math.
     
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  3. Dec 28, 2007 #2

    Doc Al

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    I'm not sure what you are talking about or what your point is. Can you restate it? A diagram would be nice.
     
  4. Dec 28, 2007 #3
    wt in motion =torque. It is possible by removing one weight at a time near the bottom of the wheel during rotation. The way to return the weight back to the top of the wheel is by way of stationary weight on a balance beam. The stationary weight on the other end of a balanced beam or scale will lift the rotating weight back to the top of the wheel by slightly more weight or percentage. The balanced beam or scale will be returned by a Leverage bar on the wheel forced down by multiple wt in rotation. The scale will not rotate the bar will.
     
  5. Dec 28, 2007 #4
    The balanced beam or scale will simply teeter toter by weight. The Leverage bar will rotate with the wheel. The leverage bar will release the balanced beam once the weight has reached the end and the weight at the end will hinge and a pin will pull to allow the bar to continue to rotate and the Balanced beam will rise by the stationary wt. The rotating wt is lifted and returned to the wheel and the process repeats. Weight will continue to rotate a wheel if the wt returns to one side and torque used for work is produced. Work produced by gravity.
     
  6. Dec 28, 2007 #5

    Doc Al

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    Realize that torque has a specific definition in physics and that "weight in motion" isn't it.

    Sounds to me that you're trying to rationalize some kind of perpetual motion machine. Is that what this is about?
     
  7. Dec 28, 2007 #6

    russ_watters

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    Also recognize that to move an object, you need to apply a force. A balance beam in equilibrium still requires a force to move it, so you can't lift the weights for free just by dropping them onto a balance beam. That's from f=ma.

    It would help if you drew yourself a diagram, that way, it'll be easier to pinpoint where you are missing an input force/energy.

    And yeah - you haven't found perpetual motion. People have been trying since the beginning of time and have wasted a lot of it on this dead end. Discovering the laws of thermodynamics should have led to the end of this foolish pursuit, but it hasn't.
     
  8. Dec 28, 2007 #7
    I believe perpetual motion is impossible. I believe that weight + motion = torque and torque can be used for work. Weight in motion on one side of a wheel creates motion, gravity will provide torque. I believe physics will make it work (not forever) but for a long long time. Weight (gravity) and motion = torque Leverage x length =%wt %wt / wtx5 = Wt >%
     
  9. Dec 28, 2007 #8
    the beam is never balanced by weight. It is balanced by length. The stationary is 1/4 % more wt than on the other end that is lifted wt for rotation. The wt that rotates is multiple. Lets say 5 wt at 20 lbs = 100 lbs. These are in rotation, but removed and replace one at a time. The stationary wt is 25 lbs so the beam with more wt will drop and the 20 lbs rotation wt will rise and back to the top. The leverage bar now needs to push the beam down. The pin catches during rotation. The leverage bar has 100 lbs the beam has 25 lbs. The beam is driven down the next wt in rotation roll or slide down hill until the end of the beam the end will hinge and pull the pin the beam is released. It is simple math.
     
  10. Dec 28, 2007 #9
    WTx5/WTx1+1/4 = WT3 3/4 A beam that is centered and balanced. You can apply wt to one end and it will move downward and raise the end with no weight. If you apply wt on the other end which is a 1/4 more it will move downward raising the other weight. Once the weight is removed there is a 1 1/4 weight more on one end. To get the end with 1 1/4 to go down you must apply more weight and that is the reason for multiple weights on the wheel. There will be 3 3/4 more weight on the wheel where the leverage bar is attached. The leverage has more weight and must go down until released by the 1wt that will hinge and pull the pin and back to 1wt and the 1 1/4 wt must go down and raise the wt.
     
  11. Dec 28, 2007 #10

    Doc Al

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    Sorry, but I don't see the point of this thread, especially since you decline to provide a diagram or clear description of what you have in mind.

    You might find this site of interest: The Physical Principles of Unworkable Devices
     
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