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Weight on an incline

  1. Sep 24, 2007 #1
    There is not really a homework problem. I just want to understand the concept here.

    See the image attached. How is it that in the free body diagram of the image shown the angle theta is from FN to the perpendicular Force applied by box to the horizontal? It is hard to describe in words. I just want to know how am I placing my angles and X,Y in a free body diagram of this setup.

    I always thought the X axis was Cos and Y was Sin but when my professor solved the problem, FN, which is vertical, was determined by FN cos(theta)

    I dont understand.

    Attached Files:

  2. jcsd
  3. Sep 24, 2007 #2


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    The two thetas are equal from similair triangles.
    Rather than trying to remmber which is cos and sin think what happens as the angle gets small, which force goes to zero ,that equals sin which goes to zero as theta is small,and which gets larger, that is cos goes to one as theta gets small.
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