# Weight pulled on Incline

1. Oct 20, 2008

### Garicup

1. The problem statement, all variables and given/known data

A weight, mass m = 80 kg , is pulled over a rough horizontal plane, mu = 0.15, by a force of magnitude F = 359 N, making an angle of 43 degrees with the plane, away from the plane. Calculate the speed of the weight d= 1.5 m away from its initial position assuming that it started from rest.

2. Relevant equations

Ff = muFn

3. The attempt at a solution

The applied force is evaluated in the x direction only (since the object remained on the floor)

therefore : Fappx = 359 cos 43 = 262.56N

Fn = mg , therefore
Ff = 0.15(80)(9.8) = 117.6N
sumFx = 262.56 - 117.6 = 144.96N

which means:::: ma = 144.96N
80a = 144.96
a = 1.812

given Vf2 = Vi2 + 2ad, and vi = 0 (rest)

then Vf2 = 2 (1.812)(1.5)

Vf = 2.33 m/s

-------> This is what Ive done on the question, im having doubts though, can anyone please verify / correct anywhere Im wrong? Please and Thank you

2. Oct 21, 2008

### JoAuSc

It seems right to me. Why do you have doubts?