Weinberg 5.9.34(adsbygoogle = window.adsbygoogle || []).push({});

"[...] Using this together with Eq. 5.9.23 gives the general antisymmetric tensor field for massless particles of helicity ##\pm 1## in the form ##f_{\mu\nu} = \partial_{ [ \mu } a_{ \nu ] }##. Note that this is a tensor even though ##a_{\mu}## is not a 4-vector."

Not a four vector? So the vector potential in the development that follows is not a vector, not Lorentz invariant, and most significantly, not generally covariant in this universe.

If ##a## is not a vector in the construction of a Lagrangian, either the action is not a scalar or the charge-current density is not a tensor, or both.

If we brush this under the carpet, a Lagrangian constructed to conserve charge is either not the Lagrangian of a conserved quantity (##dj \neq 0##) or the Lagrangian density is frame dependent, or both.

Is this later resolved?

**Physics Forums - The Fusion of Science and Community**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Weinberg 5.9.34

Loading...

Similar Threads for Weinberg | Date |
---|---|

I Is this a mistake in Weinberg's book? | Mar 25, 2018 |

I Weinberg and Ray Transformations – Ch2 App A. | Feb 23, 2018 |

A Weinberg: detecting changes to QM using atomic clocks | Feb 12, 2017 |

A Stephen Weinberg on Understanding Quantum Mechanics | Jan 4, 2017 |

I Weinberg LN in QM (Section 3.5): Momentum operator | Apr 15, 2016 |

**Physics Forums - The Fusion of Science and Community**