d20/de2+1=0 and the boundry condition is -d0/de(evaluated at e=+/- 1)=+/-H0(evaluated at +/-1). The final result yields 0(e)=(1/2)(1-e2)+1/H. What i dont understand is how to use this boundary condition and where the 1/H comes from.
The Attempt at a Solution
When i just have a B.C. of e=+/-1(0=0(zero)), I get 0=(1/2)(1-e2)). My teacher this semester really does not explain anything so i would appreciate your guy's help with this class. IT IS A NIGHTMARE!!!