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Homework Help: Weird Boundary Conditions?

  1. Feb 8, 2010 #1
    1. The problem statement, all variables and given/known data

    d20/de2+1=0 and the boundry condition is -d0/de(evaluated at e=+/- 1)=+/-H0(evaluated at +/-1). The final result yields 0(e)=(1/2)(1-e2)+1/H. What i dont understand is how to use this boundary condition and where the 1/H comes from.

    3. The attempt at a solution
    When i just have a B.C. of e=+/-1(0=0(zero)), I get 0=(1/2)(1-e2)). My teacher this semester really does not explain anything so i would appreciate your guy's help with this class. IT IS A NIGHTMARE!!!
  2. jcsd
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