Weird Parabola Problem

pythagman · May 5, 2008

1. The problem statement, all variables and given/known data
A parabolic communications antenna has a focus 6 feet above its vertex. Write an equation for the parabola and find the width of the antenna 9 feet from the vertex. Locate the origin strategically.

2. Relevant equations

y= x^2 (parent equation for parabola)

3. The attempt at a solution
focus = 4p.
standard form of parabola , (x-h)^2 = 4p(y-k)^2
4 * 6 = 24 so (x-h)^2 = 24(y-k)^2.
It doesn't give you the origin how are you supposed to write the formula?

Dick · May 5, 2008

(h,k) is the vertex. You can put the origin anywhere you like. Why not put it at the vertex? So (h,k)=(0,0). Now what's the y coordinate 9 feet from the vertex? BTW, check your standard form for a parabola. You've got an extra square in there.

sdykikyou · May 13, 2008

Hello...

Dick said: ↑

You've got an extra square in there.

I believe you're right. The equation is (x-h) = 4p(y-k)^2

or (y-k) = 4p(x-h)^2

So, just try x = 24y^2 and work from there ^^

Log in or Sign up

Weird Parabola Problem

pythagman

Dick

sdykikyou

Story Problem w/ parabolas (Replies: 8)

Bridge parabola word problem (Replies: 5)

Suspension Bridge Parabola Problem (Replies: 8)

Parabola word problem (Replies: 3)

Word Problems with Parabolas (Replies: 17)