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Weird satillite problem

  1. Jul 10, 2008 #1
    1. The problem statement, all variables and given/known data
    A man hanging upside down is holding a partner who weighs 565 N. Assume that the partner moves on a circle that has a radius of 6.50 m. At a swinging speed of 4.40 m/s, what force must the man apply to his partner in the straight-down position?

    2. Relevant equations

    I'm at a loss.

    3. The attempt at a solution

    but I am pretty sure that at the bottom of the circle the man holding up the other man must hold up a force=mg where m is the mass of the bottom partner. Therefore F=565.

    Am I being asked the centripedial force?

    I tried F(centripedal)= (525/9.8)*(4.4)2 and then divide that by the radius 6.5.

    I got 160 which is not the correct answer.
     
  2. jcsd
  3. Jul 10, 2008 #2

    rock.freak667

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    Homework Helper

    The upside-down man exerts an upward force towards the centre of the circle. The weight of his partner is downwards. The resultant of those 2 forces provides the centripetal force needed to make him move at that speed.
     
  4. Jul 10, 2008 #3
    I keep getting 160 :(

    Fc=mv2/r

    Is that not correct?
     
  5. Jul 10, 2008 #4
    Ok. I solved it. Thanks to the one person who helped me.
     
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