- #26

DrGreg

Science Advisor

Gold Member

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- 856

Unless I've completely misunderstood what you're trying to do here, there's a bit more to it than that:[tex]##x=r \, \sin\theta \, \cos\varphi##

To convert this to a transformation of differentials we differentiate

##dx= \partial_r(r \, \sin\theta \, \cos\varphi)dr##.

dx = \frac{\partial x}{\partial r} dr + \frac{\partial x}{\partial \theta} d\theta + \frac{\partial x}{\partial \varphi} d\varphi

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