A point charge of +2.7 mC is located at the origin of a coordinate system and a second point charge of -7.8 mC is at x = 1.5 m. At what point on the x axis is the electrical potential zero? Calculate to 2 decimal places.
The Attempt at a Solution
net pot. diff will be zero at
and at x = -1.
pot. diff is a scalar qty. so u can directly add it.
if the net potential diff at a pt (say at x,0) is zero,
(k*3/x) - (k*6/(1-x)) = 0
Similarly for negative x, u can make n eqn:
-(k*3/x) - (-k*6/(1+x)) = 0
which shal give u: x=-1
WHAT AM I DOING WRONG?