You need a constant of integration in that result.Alexandra Fabiello said:Homework Statement
If y' = 6x(x2+2)2 and y = 25 when x = 1, what is the value of y when x = -1?
Homework Equations
N/A
3. The Attempt at a Solution [/B]
∫6x(x2+2)2dx = 2x(x2+2)3
(12 + 3)3 + 2(1) + c = 25
1 + 2 = 3 and 2(1) = 2 and 33 = 27, so 27*2 + c = 25 so 54 + c = 25, therefore c = 25-54 = -29
Now substitute x = -1
(-1) squared is 1 and 2(-1) = -2, so 27*-2 = -54, so -54 - 29 = y = -83
WileyPlus tells me it's wrong.
What is wrong with this?
SammyS said:You need a constant of integration in that result.
Also, you made a mistake in your integration.
What is the derivative of y = 2x(x2+2)3 + C ?
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