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A What apart from geodesic distance matters in a spacetime that has lost its maximal symmetry?

  1. Dec 11, 2017 #1
    The isometry group of the anti-de Sitter spacetime is ##SO(d-1,2)##, which has a total of ##\frac{1}{2}d(d+1)## isometries.

    For the three-dimensional anti-de Sitter spacetime, these are ##6## isometries. These isometries have corresponding Killing vectors, which in global coordinates, are given in equation (9.8) of http://www.hartmanhep.net/topics2015/9-ads3symmetries.pdf.

    For an AdS##_3## cylinder (in global coordinates) that is radially cut-off at a finite radius, the number of isometries would decrease to ##2## because only ##2## of the Killing vectors in equation (9.8) of http://www.hartmanhep.net/topics2015/9-ads3symmetries.pdf are independent of the radial coordinate.

    Now, any physical quantity on a maximally symmetric spacetime is a function of the geodesic distance. How does this fact change for the radially-cut-off AdS##_3## cylinder?
     
    Last edited: Dec 11, 2017
  2. jcsd
  3. Dec 16, 2017 #2
    Thanks for the thread! This is an automated courtesy bump. Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post? The more details the better.
     
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