- #1

DethRose

- 101

- 0

im in first year electronics and have a problem with a parallel rlc circuit

im trying to find the reactance (Xc and Xl) for a circuit that has a 500 ohm resister and a .01 microfarad capacitor in parallel with a 500 ohm resistor and a .5 mH inductor. The frequency of the circuit is 50 KhZ

here are my calculations

xc= 1/(2)(pie)(50khz)(.01microfarads)

= 0.32

xl= (2)(pie)(50khz)(.0005H)

=0.157

but i had them both marked wrong...help with this would be very much appreciated