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Physics
Quantum Physics
What do these wavenumbers correspond to in Raman spectroscopy?
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[QUOTE="TeethWhitener, post: 6866036, member: 511972"] It seems like you’re trying to apply classical reasoning to a quantum problem. Photons are indistinguishable: they don’t have labels. (Note that it’s kind of difficult to discuss Raman spectroscopy at B level) Raman spectroscopy relies on inelastic scattering of photons off a material. A rough classical picture of the Raman effect is that an incoming photon “bounces off” a molecule, causing the molecule to be vibrationally excited. Since energy is conserved, whatever energy is not deposited in the molecular vibration exits the system as a lower energy photon. However, you can’t say this is the “same” photon or “different,” because photons are indistinguishable (NB—this is true even when the photons are the same energy, as in reflection or Rayleigh scattering). In terms of intensity, certain vibrational modes of a molecule have certain cross sections, which will tell you how efficient the Raman scattering process is for them. The light detected in a Raman spectrum is much less intense than the Rayleigh scattered light, which is itself much less intense than the incoming laser light. [/QUOTE]
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Quantum Physics
What do these wavenumbers correspond to in Raman spectroscopy?
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