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Physics
Quantum Physics
Quantum Interpretations and Foundations
What does delayed choice entanglement swapping require?
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[QUOTE="DrChinese, post: 6829242, member: 323"] 1. All of this is correct, and I agree. Preparation alone does not entangle 1 & 4. When a successful swap operation is executed (one of the 4 Bell states), "[I]you prepare a specific entangled state of photons 1 and 4 without a causal interaction with either of these photons.[/I]" Couldn't have said it better myself. :smile:2. This basically states the exact opposite of 1, so of course I disagree. There is no "[I](post-)selection of specific subensembles for which photons 1 and 4 are entangled.[/I]" No subensembles of 1 & 4 are ever entangled UNLESS the swap occurs. You know this because of monogamy of entanglement (and hopefully I don't need to convince you about that). If a successful the swap occurs, 1's monogamous entanglement with 2 ceases and its monogamous entanglement with 4 begins. In sum: If you don't perform any swapping at all, there is no sub-ensemble of 1 & 4 pairs that are ever entangled. (And again, hopefully I don't need to convince you about that.) Also: Your use of the word "causal" in this section is ambiguous. Since quantum nonlocality defies Einsteinian causality, it is not a valid descriptor for the swapping action. Time ordering of events within a full quantum context is not a factor in any case. 3. I split the sections up as requested. [/QUOTE]
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Quantum Interpretations and Foundations
What does delayed choice entanglement swapping require?
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