- #1

jaja1990

- 27

- 0

**What does "H" mean?!**

I have this question in my assignment paper:-

8. Sketch the graph of:

(a)

y = |2x − 2|;

(b)

y = 2H(x − 4)

(a) is obvious, but how do I sketch (b)? Does "H" stand for some specific constant?

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- Thread starter jaja1990
- Start date

- #1

jaja1990

- 27

- 0

I have this question in my assignment paper:-

8. Sketch the graph of:

(a)

y = |2x − 2|;

(b)

y = 2H(x − 4)

(a) is obvious, but how do I sketch (b)? Does "H" stand for some specific constant?

- #2

JJacquelin

- 801

- 34

- #3

jaja1990

- 27

- 0

The webpage in the link you've given says:-

The function is:-

0 when x < 0,

1/2 when x = 0,

1 when x > 0.

But here: http://simple.wikipedia.org/wiki/Heaviside_Function, defines the function as:-

1 when x => 0,

0 when x < 0.

To begin with, which should I follow?

- #4

JJacquelin

- 801

- 34

I think that H(0)=0 correponds to an old definition remaining from history and that the standard definition is with H(0)=1/2.

Generally this is of no consequence in particle applications.

- #5

chiro

Science Advisor

- 4,815

- 134

Generally this is of no consequence in particle applications.

If one wanted to use an approximation like a Fourier series version, then it makes sense to define H(0) as 1/2 based on properties of Fourier series when you have this kind of 'Gibbs' phenomenon.

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