- #1

- 323

- 0

## Homework Statement

http://people.math.carleton.ca/~mezo/A6math1102-11.pdf

number 2a)

## Homework Equations

## The Attempt at a Solution

I just need help knowing what Re means. I've never seen it before and the prof didn't mention it.

- Thread starter kramer733
- Start date

- #1

- 323

- 0

http://people.math.carleton.ca/~mezo/A6math1102-11.pdf

number 2a)

I just need help knowing what Re means. I've never seen it before and the prof didn't mention it.

- #2

- 62

- 0

"real part of", it is defined in question 2a:

where Re(a + bi) = a for a; b 2 R

where Re(a + bi) = a for a; b 2 R

- #3

- 323

- 0

Thanks. But now i'm confused at the problem.I'm not sure how to confirm the real parts.

Last edited:

- #4

Deveno

Science Advisor

- 906

- 6

for example:

<(2+3i,4-5i),(3,1-i)> = (2+3i)(3) + (4-5i)(1+i) = 6+9i + (4-(-5) + (4 - 5)i)

= 6+9i + 9-i = 15+8i, and the real part of this is 15.

- #5

Ray Vickson

Science Advisor

Homework Helper

Dearly Missed

- 10,706

- 1,728

You can also get the real part of a complex quantity z: [tex] \mbox{Re}(z) = \frac{1}{2}(z + \bar{z}), [/tex] where [itex] \bar{z} [/itex] is the complex conjugate of z.

for example:

<(2+3i,4-5i),(3,1-i)> = (2+3i)(3) + (4-5i)(1+i) = 6+9i + (4-(-5) + (4 - 5)i)

= 6+9i + 9-i = 15+8i, and the real part of this is 15.

RGV

- Replies
- 1

- Views
- 1K

- Replies
- 2

- Views
- 3K

- Replies
- 1

- Views
- 581

- Replies
- 0

- Views
- 1K

- Replies
- 4

- Views
- 3K

- Last Post

- Replies
- 0

- Views
- 748

- Last Post

- Replies
- 2

- Views
- 373

- Last Post

- Replies
- 3

- Views
- 872

- Last Post

- Replies
- 7

- Views
- 441

- Last Post

- Replies
- 0

- Views
- 956