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I don't know about others but I have no interest in getting a kink in my neck turning my head sideways just because you can't be bothered to show your image right-side-updRic2 said:I'm Sorry for the vague title, but I don't know what to write. Can someone tell me the meaning of the passage I underlined?
Thank you
RicView attachment 224159
Neither one. I was making a statement of fact.dRic2 said:Wow, I don't know if you were trying to be funny or mean.
DrClaude said:@dRic2: What book does this come from?
First of all thank you very much for the effort.Mark44 said:I've put a fair amount of time into this problem today
The best answer I can come up with is that the above means "if v is replaced by the eigenvalue ##v_L##..." Other than that, no idea.dRic2 said:First of all thank you very much for the effort.
I'm familiar with eigenvalues/eigenfunctions thanks to quantum mechanics. But I can't even understand the meaning of this. The operator ##L## refers to the function ##\delta(z)## so what does "if v has the eigenvalue..." mean? How can v have an eigenvalue if the differential equation is written for ##\delta##?
DrClaude said:Given the diffusivity ##\alpha## and the Arrhenius parameters ##A## and ##E##, then the equation has a non-trivial solution ##\delta(z)## only for a particular value of ##v##, which is then called an eigenvalue.
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