What equation should I use?

  • Thread starter get_rekd
  • Start date
  • #1
39
0
how do you figure out how long it take's an object launched vertically upwards to reach its apex?
V=29.4 m/s
 

Answers and Replies

  • #2
158
0
v(final)= Vo + a(t) (a= -9.8)
 
  • #3
39
0
so
-29.4 m/s = 29.4 m/s + -9.8t?

-58.8 m/s = -9.8t
----------- ------
-9.8 -9.8

6s = t to reach apex
 
Last edited:
  • #4
158
0
Vo is given
 
  • #5
158
0
no when it reaches its apex (highest point), the ball has a speed of zero
 
  • #6
39
0
yeah so it is v(final)=29.4 m/s + a(t)
but doesn't an object come back down at the same velocity that it went up?
that is why I thought:
-29.4 m/s = 29.4 m/s + a(t)
 
  • #7
158
0
right, thats true. but thats not what the question asks. It asks when it reaches its highest point, at the highest point the velocity is 0
 
  • #8
39
0
okay so then I should set final velocity to = 0 m/s?

0 m/s = 29.4 m/s + -9.8t
-29.4 m/s = -9.8 t
---------- -------
-9.8 -9.8

t = 3 s ?
 
  • #9
39
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anybody?
 
  • #10
158
0
yo, thats right
 
  • #11
39
0
thanks
 

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