A .22 rifle bullet, traveling at 350 m/s, strikes a block of soft wood, which it penetrates to a depth of 0.130 m. The block of wood is clamped in place and doesn't move. The mass of the bullet is 1.80 g. Assume a constant retarding force.(adsbygoogle = window.adsbygoogle || []).push({});

1.) What force, in newtons, does the wood exert on the bullet?

using Newton's Second Law (F=ma)

first i had to finda

v^2f = V(0)^2 + 2ax <--- equation of motion

0=350^2+2(a)(0.130)

a = 471153.8462

then plug in known values for newton's second law

F = (1.80)(471153.8462) = 848076 N

or 8.48×10^5 N

but it's the wrong answer, can someone help?

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# Homework Help: What force, in newtons, does the wood exert on the bullet?

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