A .22 rifle bullet, traveling at 350 m/s, strikes a block of soft wood, which it penetrates to a depth of 0.130 m. The block of wood is clamped in place and doesn't move. The mass of the bullet is 1.80 g. Assume a constant retarding force. 1.) What force, in newtons, does the wood exert on the bullet? using Newton's Second Law (F=ma) first i had to find a v^2f = V(0)^2 + 2ax <--- equation of motion 0=350^2+2(a)(0.130) a = 471153.8462 then plug in known values for newton's second law F = (1.80)(471153.8462) = 848076 N or 8.48×10^5 N but it's the wrong answer, can someone help?