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Sanev
I want to ask if we now the energy of a planet (mc2) and we divided that energy over the radius(R) of that planet what kind of force(F) we get --> mc2/Radius = F(?)
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The equation m.c^2/Radius represents the centripetal force required to keep an object with mass (m) moving in a circular motion at a constant speed (c) with a given radius (Radius). This force acts towards the center of the circle and is necessary to maintain the circular motion.
The equation m.c^2/Radius is derived from Einstein's famous equation, E=mc^2. It represents the kinetic energy (E) of an object with mass (m) moving at a constant speed (c) in a circular motion with a given radius (Radius). This kinetic energy is equal to the product of the mass and the square of the speed of light (c^2), divided by the radius.
No, m.c^2/Radius cannot be negative. This is because the speed of light (c) and the radius (Radius) are always positive values, and the mass (m) cannot have a negative value in this equation.
The value of m.c^2/Radius is directly proportional to the radius (Radius). This means that as the radius increases, the centripetal force required to keep the object in circular motion also increases. Similarly, if the radius decreases, the force required decreases as well.
No, m.c^2/Radius is not considered a fundamental force in physics. It is a derived equation that helps us understand the relationship between mass, speed, and radius in circular motion. The fundamental forces in physics are gravity, electromagnetism, strong nuclear force, and weak nuclear force.