Calculating the Force of a Planet Using Energy and Radius

In summary, the conversation discusses the energy of a planet and how it relates to force. When dividing the planet's energy by its radius, the resulting quantity has the same unit as a force but is not actually a force and has no practical use. When multiplied by fundamental constants, it represents the ratio of an object's radius to its Schwarzschild radius, indicating if it would be a black hole. The relevance of this quantity is questioned, with an example of a similar calculation having no practical use. A link to a related topic is shared and the conversation concludes with understanding and gratitude.
  • #1
Sanev
I want to ask if we now the energy of a planet (mc2) and we divided that energy over the radius(R) of that planet what kind of force(F) we get --> mc2/Radius = F(?)
 
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  • #2
That quantity has the same unit as a force, but it is not a force anywhere, and it has no relevance.

If you multiply it by a few fundamental constants you get the ratio of the object’s radius to its Schwarzschild radius (if it would be a black hole). If that ratio is smaller than 1 then you don’t have a planet, you have a black hole.
 
  • #3
I'm sorry but i don't understand this IT HAS NO RELEVANCE. Why it doesn't have? Can you explain a little bit more. Thank you!
 
  • #4
Multiply the width of your thumb by the number of days in a year and divide it by the duration of your last breakfast. The result has the units of a speed. Do you expect the result to have any relevance? Why not?
 
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  • #6
I get it :D thank you for your answer :)
 

1. What is the significance of m.c^2/Radius?

The equation m.c^2/Radius represents the centripetal force required to keep an object with mass (m) moving in a circular motion at a constant speed (c) with a given radius (Radius). This force acts towards the center of the circle and is necessary to maintain the circular motion.

2. How is m.c^2/Radius related to Einstein's famous equation, E=mc^2?

The equation m.c^2/Radius is derived from Einstein's famous equation, E=mc^2. It represents the kinetic energy (E) of an object with mass (m) moving at a constant speed (c) in a circular motion with a given radius (Radius). This kinetic energy is equal to the product of the mass and the square of the speed of light (c^2), divided by the radius.

3. Can m.c^2/Radius be negative?

No, m.c^2/Radius cannot be negative. This is because the speed of light (c) and the radius (Radius) are always positive values, and the mass (m) cannot have a negative value in this equation.

4. How does the radius affect the value of m.c^2/Radius?

The value of m.c^2/Radius is directly proportional to the radius (Radius). This means that as the radius increases, the centripetal force required to keep the object in circular motion also increases. Similarly, if the radius decreases, the force required decreases as well.

5. Is m.c^2/Radius a fundamental force in physics?

No, m.c^2/Radius is not considered a fundamental force in physics. It is a derived equation that helps us understand the relationship between mass, speed, and radius in circular motion. The fundamental forces in physics are gravity, electromagnetism, strong nuclear force, and weak nuclear force.

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