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Homework Statement
Julie tightened herself fastened a set of bathroom spring scales to a platform and went down a 30 degree slope. No friction was present and the platform supporting the scales was HORIZONTAL. what fraction of her true weight was indicated by the scales?
The Attempt at a Solution
so what i did was just assume a random mass, in this case 50kg so that means around 500 Newtons.
Therefore, Fnormal would be 500 cosine 30 = 433 Newtons
than all i did was take 433 and divide it by 500 which gives me 0.866. So is it right to say that 87% of her true weight will be shown on the scale?