Earlier I asked for help about a high voltage power supply, and I was told not to worry too much about 20k volts because they have a very low current I was left thinking about that say whatever circuit that ends in an inductor and generates that voltage of 20k volts. and I was told that the current runs at around 200 mA how does this work? I mean I was taught that V=iR and AFAIK the resistance of a wire (whatever material) is dictated by its material properties, its density and whatnot, so even tho its not a "perfect wire" it exhibits certain resistance R that should be (should be?) fixed, right? so If R is fixed, how can V and i be fixed too? example: I found a table that says that copper wire has 0.001588 Ohms per foot lets say I have a 10 ft wire running those 20kV, so that means that the current i= V/R should be 20000 V / (.001588*10) Ohms= 1259445.84383 Amps how come the current is 200 mA ? is there some alteration to Ohms law or whats going on here?