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My solution is first to find out the current flows before and after the switch is closed through each resistor. I redrew the circuit into two circuits in series. First one is when switch is opened (R1,R34--I combined R3,R4 in parallel), the second one is when switch is closed (R1,R234--combined R2 with R34). Then I figured out that R234 < R34. Since V=IR. Now I am looking for the change in current before and after. My teacher told me current after the S is closed is bigger than the current when the S is opened? BUt is that because when you add more resistance to the circut, the current through the circuit will decrease? which in this case R234<R34, that's why I is more when the switch is closed?

Thanks.