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What is a value of psi* for a particle in 1D box stationary state?

  1. Feb 13, 2005 #1
    I know that psi is equal to (2/a)^1/2 sin(n pi x/a)? what is psi*?
     
  2. jcsd
  3. Feb 13, 2005 #2

    dextercioby

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    Complex conjugate of "psi"...In your case,it's identical to "psi"...

    Daniel.
     
  4. Feb 13, 2005 #3

    Gokul43201

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    How is [itex]\psi^*[/itex] defined ? Or simpler still, what does the * do ?
     
  5. Feb 14, 2005 #4

    jtbell

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    Actually, including the time dependence, it's

    [tex]\Psi(x,t) = \sqrt {\frac {2} {a}} \sin \left (n \pi \frac {x} {a} \right ) \exp \left (-i \frac {E_n} {\hbar} t \right ) [/tex]

    so the complex conjugate is

    [tex]\Psi^*(x,t) = \sqrt {\frac {2} {a}} \sin \left (n \pi \frac {x} {a} \right ) \exp \left (i \frac {E_n} {\hbar} t \right ) [/tex]

    The complex conjugate means simply, change i to -i (and -i to i) everywhere.
     
    Last edited: Feb 14, 2005
  6. Feb 14, 2005 #5

    dextercioby

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    In that case,he (probably) would have spelled "Psi"...He didn't intend to include the time dependence...

    Daniel.
     
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