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## Homework Statement

A 81-g ice cube at 0°C is placed in 878 g of water at 25°C. What is the final temperature of the mixture?

## Homework Equations

No heat is loss therefore m*Cp*deltaT+m*Cp*deltaT=0

Cp ice=2.09

Cp water=4.19

## The Attempt at a Solution

878*4.19*(Tf-25)+81*2.09*(Tf-0)=0

3678.82Tf+169.29Tf=91970.5

Tf=23.9C

The answer is wrong...don't know why...