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Could someone kindly explain to me what

In other words, given a projectile launched at [tex]\theta$[/tex] above the horizontal with an initial velocity of [tex]v_0[/tex], how do we calculate the hang time?

The maximum height of the trajectory is [tex]|1/2gt_2^2|[/tex]. We can use this in the equation [tex]s_y=v_{0y}t_1-1/2gt_1^2[/tex] to find [tex]t_1[/tex].

I am rather confused...some posts I saw while browsing the forums said that the initial velocity does not affect the "hang time".

Thank you

TS

**hang time**is, in the context of 2D projectile motion? Enlighten me on the equations of motion that might be applicable to such a problem.In other words, given a projectile launched at [tex]\theta$[/tex] above the horizontal with an initial velocity of [tex]v_0[/tex], how do we calculate the hang time?

**Thoughts.**We need to calculate the time it takes for the projectile to reach the maximum height of the trajectory ([tex]t_1[/tex]), and the time it takes to hit the ground*after*attaining its maximum height ([tex]t_2[/tex]), and then add up [tex]t_1+t_2[/tex]. I think that it will be convenient to use the y-component of [tex]v_0[/tex].The maximum height of the trajectory is [tex]|1/2gt_2^2|[/tex]. We can use this in the equation [tex]s_y=v_{0y}t_1-1/2gt_1^2[/tex] to find [tex]t_1[/tex].

I am rather confused...some posts I saw while browsing the forums said that the initial velocity does not affect the "hang time".

Thank you

TS

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