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- Thread starter nehach
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CompuChip

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If you have a vector (in, say, three dimensions) [tex]\vec x = (x_1, x_2, x_3)[/tex] then the magnitude of that vector is given by (Pythagoras): [tex]|\vec x| = \sqrt{x_1^2 + x_2^2 + x_3^2}[/tex].

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tiny-tim

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Hi nehach ! Welcome to PF!

"magnitude" is a long word which means something very simple.

As

For example, if something is displaced along the x-axis by 3, then the magnitude of its displacement is also 3.

But if something is displaced along the x-axis by -3, then the magnitude of its displacement is still 3.

(magnitude is always positive, or zero.)

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Displacement is a vector quantity defined as the change in position - from an initial point i to a final point f. Its magnitude is the length of the straight line between i and f and its direction is from i to f. The actual path taken is irrelevant.

Distance is a scaler quantity defined as the path length, i.e., it does depend on the actual path taken. Distance only equals the magnitude of the displacement for straight line paths.

Hope this hepls

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distance between i and f is 5 km

i ----------5KM------------f

now kindly tell me what is magnitude and what is displacement

kindly tell me the formula how to calculate both of them

because i am confisued in this

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tiny-tim

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Hi nehach!

Displacement: 5 km East.

Magnitude: 5 km.

Displacement: 5 km East.

Magnitude: 5 km.

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thanks tiny-tim now its clear to me

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we can discuss any problem directly

if u think ok

kindly give me ur gmail id

and kindly tell me the formula of calulating both displacement and magnitude

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You can use the formula posted by

Sorry if I said something wrong

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rcgldr

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thanks jeff i got it

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symbolipoint

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http://en.wikipedia.org/wiki/Absolute_magnitude

... not meant as distraction nor argument.

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