What is the acceleration of the block?

In summary: The block is sitting on a slope, so the normal force is the only force on it. The block is being pulled by a force of 250N, and the coefficient of friction is 0.200. So the acceleration of the block is .412 m/s2.
  • #1
Angela_vaal
59
1

Homework Statement


A 50.0-kg block is being pulled up a 16.0° slope by a force of 250 N that is parallel to the slope. The coefficient of kinetic friction between the block and the slope is 0.200. What is the acceleration of the block?

Homework Equations


FkkN
F=MA

The Attempt at a Solution


answer is .412 m/s2. I know the answer I just don't know the steps to solve this equation.
It is saying it is being pulled up, does that mean it has tension instead of normal force? it is not sitting on anything so it can not have a normal force right?
 
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  • #2
Angela_vaal said:
answer is .412 m/s2. I know the answer I just don't know the steps to solve this equation.
You don't even have an equation to solve, and how do you know that is the right answer?
It is saying it is being pulled up, does that mean it has tension instead of normal force? it is not sitting on anything so it can not have a normal force right?
Surely the block is sittig on a slope? A tension is a force. Is the block being pulled by a rope or has someone just grabbed it and pulled it? Does it matter to the question?

Your first step is to sketch a free body diagram ... you will have course notes about this: so how many forces are on the block, and what are they?
 
  • #3
Simon Bridge said:
Surely the block is suittig on a slope?
Your first step is to sketch a free body diagram ... you will have course notes about this: so how many forces are on the block, and what are they?

In that case, there is a normal force. So the forces on the block are the Normal force, MG and 250cos16, 250 sin16
 
  • #4
Identify the forces themselves - you have a normal force to the slope, gravity, friction, and the pulling force.
GIve them names - so you have ##F_g=mg## pointing vertically down, ##N## points upwards at 90deg to the slope, ##f=\mu N## points down the slope and ##F=250##N points up the slope. F is only one force, not two like you wrote. Don't do the cosine and sine stuff untilyou decide how to orient your axes - hint: point x-axis up the slope.
 

1. What is acceleration?

Acceleration is the rate of change of velocity over time. It is a vector quantity, meaning it has both magnitude and direction.

2. How is acceleration different from velocity?

Velocity is the rate of change of position over time, while acceleration is the rate of change of velocity over time. Velocity is a vector quantity, while acceleration is a vector quantity.

3. How is acceleration calculated?

Acceleration is calculated by dividing the change in velocity by the change in time, using the formula a = (vf - vi) / t, where vf is the final velocity, vi is the initial velocity, and t is the time interval.

4. What are the units of acceleration?

The standard unit of acceleration is meters per second squared (m/s²) in the SI system. Other common units include feet per second squared (ft/s²) and kilometers per hour squared (km/h²).

5. What factors affect the acceleration of an object?

The acceleration of an object can be affected by the net force acting on the object and the mass of the object. According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force and inversely proportional to the mass.

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