What is the cause of normal stress on a fluid element?

In summary, pressure is the isotropic part of the stress tensor and it is not the cause of stress. Static and dynamic pressure are due to volume viscosity.
  • #1
benny_91
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5
In the derivation of Navier Stokes equation there is a term for normal stress acting on the fluid element. While the cause of normal stress is the static pressure which is already present in the equation doesn't this mean that the same force on the fluid element is repeated twice with different names?
 
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  • #2
Pressure is the isotropic part of the stress tensor by definition. It is not the cause of stress.
 
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  • #3
we know that stress is a result of resistance to externally applied force. For example shear stress is a result of resistance to viscous force acting between fluid layers. On the same lines could you please tell me the cause of normal stress on fluid elements?
 
  • #4
benny_91 said:
we know that stress is a result of resistance to externally applied force. For example shear stress is a result of resistance to viscous force acting between fluid layers. On the same lines could you please tell me the cause of normal stress on fluid elements?
Hm, this may partly be a question of wording, but shear stress is the force per surface acting parallel to a given surface. In the case of liquids I would consider it to be rather the cause of shearing than the result of something. In the case of pressure, pressure is the cause of volume change but admittedly, you may look at it just the other way round. There is a difference between static and dynamic pressure which is due to volume viscosity, the latter being somewhat hard to grasp. My favourite example is the following:
Consider nitrogen dioxide in the production which you, as an aircraft engineer you, will be heavily involved. It is also used as a rocket propellant.
At room temperature it has an interesting property, namely it is partially dimerised:
## \mathrm{2NO_2\leftrightharpoons N_2O_4}##
By the law of mass action, you can change this equilibrium changing the volume available to the gas. Upon compression, more N2O4 will be formed and on decompression more NO2. However, equilibrium is not established instantaneously but takes some time. That means that if you compress this gas rapidly, its pressure will be higher as when you compress it slowly, despite both components behaving nearly like ideal gases. That's an example of dynamic pressure and volume viscosity. It will be present for all real gases as the gas molecules attract due to van der Waals interactions and the establishment of a new distance distribution upon compression takes some time, too.
 
  • #5
In a Newtonian fluid, for which the Navier Stokes equations apply, the normal stresses involve a combination of a contribution from pressure and a contribution from viscous stresses. Even though, as novices, we learn that viscous shear stresses are caused by velocity gradients normal to the velocity vector, when this is properly (tensorially) generalized to 3 dimensions, we find that the viscous contribution of normal stress is determined by the gradient of the velocity component in the direction of that velocity component. The pressure contribution and the viscous contribution are each expressed as separate terms in the Navier Stokes equations. Even in pure shear flow between parallel plates, if we rotate the coordinate axes, we find that there are viscous normal components of stress in the new coordinate directions. For more details on this, see Chapter 1 of Transport Phenomena by Bird, Stewart, and Lightfoot.
 
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  • #6
Namely in the main axis frame of the stress tensor, there are only normal stresses.
 
  • #7
DrDu said:
Namely in the main axis frame of the stress tensor, there are only normal stresses.
And, for a fluid that is deforming, these principal normal stresses include viscous contributions.
 
  • #8
DrDu said:
Namely in the main axis frame of the stress tensor, there are only normal stresses.
The rotated axes I described in post #5 are not necessarily principal directions of stress, and, for these axes, there are still normal stress components in the coordinate directions.
 
  • #9
So you mean to say that normal stresses in moving fluid are caused by viscocity as well as static pressure. Did I get it right?
 
  • #10
benny_91 said:
So you mean to say that normal stresses in moving fluid are caused by viscocity as well as static pressure. Did I get it right?
Yes
 
  • #11
So does this mean that part of the static pressure force acting on the fluid element causes it to accelerate while the other part deforms it volumetrically thereby producing normal stress in the fluid element under consideration?
 
  • #12
benny_91 said:
So does this mean that part of the static pressure force acting on the fluid element causes it to accelerate while the other part deforms it volumetrically thereby producing normal stress in the fluid element under consideration?
No. The static pressure force contributes to acceleration and deforming, as does the viscous force, since both of these add up to the total force (neglecting gravity). And volumetric deformation is only one of the infinite range of deformations that a fluid can experience. All these deformations contribute to the viscous portion of the stress tensor. Furthermore, incompressible fluids do not experience volumetric deformation at all. Are you aware of the relationship between the velocity gradients, the pressure, and the components of the stress tensor.
 
  • #13
No I am not aware of the relationship. Please could you direct me to the proper book or online material where i can read and understand it?
 
  • #14
benny_91 said:
No I am not aware of the relationship. Please could you direct me to the proper book or online material where i can read and understand it?
Transport Phenomena, Bird, Stewart, and Lightfoot
 
  • #15
$$\sigma_{i,j}=-p\delta_{i,j}+\eta\left(\frac{\partial v_i}{\partial x_j}+\frac{\partial v_j}{\partial x_i}\right)$$
where ##\sigma_{i,j}## is a component of the stress tensor, p is the pressure, ##\delta_{i,j}## is the isotropic identity tensor, ##\eta## is the fluid viscosity, ##v_i## is a component of the velocity vector, and ##x_i## is a Cartesian spatial coordinate. This is the equation for the components of the stress tensor in terms of the pressure and the velocity gradients, for a Newtonian fluid. Note the separate contributions of the pressure and the viscous term to the overall stress.
 
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1. What is normal stress on a fluid element?

Normal stress on a fluid element refers to the force per unit area that is exerted on the fluid element in a direction perpendicular to its surface. This stress can be caused by different factors, such as gravity, pressure, or flow velocity.

2. What are some common causes of normal stress on a fluid element?

The most common causes of normal stress on a fluid element are gravity, pressure differences, and the velocity of the fluid. These forces can act individually or in combination to create stress on the fluid element.

3. How does gravity affect normal stress on a fluid element?

Gravity can cause normal stress on a fluid element by creating a pressure gradient, with higher pressure at the bottom and lower pressure at the top. This pressure gradient creates a force that acts perpendicular to the surface of the fluid element, resulting in normal stress.

4. How does the velocity of a fluid affect normal stress on a fluid element?

The velocity of a fluid can create normal stress on a fluid element through shear stress. When a fluid is moving, different layers of the fluid will move at different speeds, creating a velocity gradient. This velocity gradient results in shear stress, which acts perpendicular to the fluid element's surface and contributes to its overall normal stress.

5. What factors can influence the magnitude of normal stress on a fluid element?

The magnitude of normal stress on a fluid element can be influenced by several factors, including the density and viscosity of the fluid, the size and shape of the fluid element, and the external forces acting on the fluid. Additionally, the type of flow (such as laminar or turbulent) can also affect the magnitude of normal stress on a fluid element.

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