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What is the current in the wire?

  1. Jul 23, 2011 #1
    1. The problem statement, all variables and given/known data

    A square ammeter has sides of length = 8.4 cm. The sides of the ammeter are capable of measuring the magnetic field they are subject to. When the ammeter is clamped around a wire carrying a DC current, as shown in the figure, the average value of the magnetic field measured in the sides is 4.4 G. What is the current in the wire?

    http://www.webassign.net/bauerphys1/28-p-026-alt.gif

    3. The attempt at a solution


    B*4*L=Mo*I

    i used this formula

    so I = B*4*L/Mo

    I = 0.00044 T* 4 * 0.0084 m / (4 pi * 10^-7 ) = 117 A

    it's not right it's a little bit off from the answer i think

    help?
     
    Last edited: Jul 23, 2011
  2. jcsd
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