- #1
november1992
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Homework Statement
A 3 m long copper wire that has a diameter of 6 mm is connected to a 9 V battery.
a) What is the current through the wire?
b) If wire a was connected to a battery for 1 second, how much energy would the wire dissipate?
Homework Equations
A = [itex]\pi[/itex][itex]r^{2}[/itex]
R = [itex]\rho[/itex][itex]\frac{L}{A}[/itex]
i = [itex]\frac{V}{R}[/itex]
[itex]\rho[/itex] = 1.72 x [itex]10^{-8}[/itex]
P = i * V
W = P * t
The Attempt at a Solution
I got:
R = 1.82mΩ
i = 4945 A
p = 44505.45
I'm unsure of my answers. The values seem to be too high.
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