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What is the derivative for arctan(2/x)?

  • Thread starter EvLer
  • Start date
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What is the derivative for

arctan(2/x)?

I know it's generally: [(1/a)arctan(x/a)]' = 1/(x^2 + a^2); but in my case its x^-1!

Thanks for any help.
 

quasar987

Science Advisor
Homework Helper
Gold Member
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The formula to remember is

[tex]Arctg'(x) = \frac{1}{1+x^2}[/tex]

So using the chain rule,

[tex]Arctg'(f(x)) = \frac{f'(x)}{1+[f(x)]^2}[/tex]

which gives the derivative of Arctg for any argument.
 

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